Let several text stages share one named look
A picture with a title, a caption and a credit meant typing the same font, size and colour into every text stage, and changing the look meant typing them all again. A project now holds named styles: a stage follows one, and editing it moves every stage that follows it at once. The front-ends learn nothing effect-specific. A ParamSpec can be marked .styled(), saying a style carries it rather than the stage, and Effect::styleKind() names the pool it comes from -- so styleSpecs(kind) is to a style what params() is to a stage, and a second text-ish effect would slot into the styles that already exist. The look is what a style carries; the words and the placement stay on the stage, which is what lets two stages share a typography in two different corners. stageValues() resolves one in a single place, and a stage keeps a full set of values of its own beside the style, so switching it to Custom, dropping the style, or opening the project in a build that does not know it renders exactly the same picture. A style moves stages together; it never holds the only copy of anything. The command line builds no styles and passes none, so it renders what it always did. Co-Authored-By: Claude Opus 5 <noreply@anthropic.com>
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#include "core/style.hpp"
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#include <algorithm>
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#include "core/registry.hpp"
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namespace effector {
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std::vector<ParamSpec> styleSpecs(const std::string& kind) {
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std::vector<ParamSpec> specs;
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if (kind.empty()) return specs;
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for (const auto& effect : effects()) {
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if (effect->styleKind() != kind) continue;
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for (const auto& spec : effect->params()) {
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if (!spec.inStyle) continue;
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const bool known = std::any_of(specs.begin(), specs.end(), [&](const ParamSpec& seen) {
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return seen.key == spec.key;
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});
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if (!known) specs.push_back(spec);
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}
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}
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return specs;
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}
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ParamValues styleDefaults(const std::string& kind) {
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ParamValues values;
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for (const auto& spec : styleSpecs(kind)) values[spec.key] = paramDefault(spec);
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return values;
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}
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const Style* findStyle(const StyleSet& styles, const std::string& kind, const std::string& name) {
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if (kind.empty() || name.empty()) return nullptr;
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for (const auto& style : styles) {
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if (style.kind == kind && style.name == name) return &style;
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}
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return nullptr;
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}
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} // namespace effector
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